| The density of gravitation corridor is possible to count | | | | small distance |
| by quite an easy way. Gravitation forms a straight | | | | Time to go in cutting two lines distance is as follows:t = |
| connection for instance between sun and earth. | | | | x/ v = (0.729 x 10 to power of -84/(54513.89 m/s) = |
| Gravitation caorridor is formed by straight lines. | | | | 1.3379 x 10 to power of -87 s. |
| It is possible to calculate how many times in time unit | | | | Cutting amount how many times earth cuts gravitation |
| earth cuts gravitation corridor lines. On the basis of | | | | corridor lines in time unit when heart beats 76 1/min is |
| these calculations can be calculated heart beat which | | | | as followes: |
| is approxomately 76 !/min. | | | | G(X) = (76 1/min)/(1.3379 x 10 to power of -87 s)x(10 |
| On the calculation we know that F(GR) is a vacuum | | | | to power of -87 s) = 1.33 x 10 to power of 93 pc. |
| value all around the Universe. Distance between | | | | Finally we get radius of earth as follows: |
| gravitation lines can be calculated by a known | | | | G(X) x 86400s = 114912.00 x 10 to power of 93 = |
| equation 2 x pii x r. r is value of 1 AU (one | | | | 1.14912 x 10 to power of 87 (amount of how many |
| astronomical unit) when we know the amiunt of | | | | times earth cut the gravitation corridor lines). |
| graviatation lines which is the vakue of n. We get as | | | | G(X) x (31.00 x 10 to power of -87) = 2 x pii x Rj and |
| result the distance x which is the value of distance | | | | Rj = (4.124 x 10 to power of 7)/(2 x pii) = 0.65669 x 10 |
| between gravitation lines. | | | | to power of 7 m = 6566.9 km. |
| By heart beat that is supposed to be 76 1/min we | | | | Heart beat can be calculated as follows: |
| can calculate the amount of cuttings in time unit of | | | | Rj = 6356.912 km |
| gravitation lines. This value is G(x). | | | | 2 x pii x Rj = s = 39942 km = 3.99 x 1o to power of 7 |
| As the result of alll these calculations we get result the | | | | ms/2 = 2 x 10 to power of 7 m and v = 43200 x 10 to |
| radius of earth. This is Rj. | | | | power of 7 m/s = 4.31 x 10 to power of 3 m/snx = pii |
| Gravitation force is as follows: | | | | x rx = (pii x r)/n = 3091459 x 10 to power of -92 m = |
| F(GT) = 2.47 x 10 to power of 20 N | | | | 3.09 x 10 to power of -86 mt = (3.09 x 10 to power of |
| Energy in the gravitation corridor is as follows: | | | | -86 m9/4.32 x 10 to power of 3 m/s) = 0.715 x 10 to |
| E = F(GT) x Rj = 2.47 x 10 to power of 20 N x 1.5 x | | | | power of -89 s |
| 10 to power of 9 m | | | | X = 106 x 10 to power of 89 pc |
| = 3.705 x 10 to power of 29 Nm (J) | | | | X(t) = 4.3 x 10 to power of 3 m/s = 4.3 x 10 to |
| Distance between gravitation lines is as follows:n x = | | | | power of 3 m |
| 82 x pii) r/2 = pii x r | | | | Heart beats (86400 s) x (76 1/min) = (86400 s) x |
| x = pii x r/n = 8pii) x 1.5 x 10 to power of p m/(6.46 x | | | | (1.66666667 1/s) = 109440 1/day |
| 10 to power of 93 pc = | | | | That´s it for this time! |
| 0.729 x 10 to power of -84 m, a very very | | | | |